In this article, we’ll take a look at how we will initialize an array in C.
There are different ways through which we can do this, so we’ll list them all one by one. Let’s get started!
Method 1: Initialize an array using an Initializer List
An initializer list initializes elements of an array in the order of the list.
For example, consider the below snippet:
|
1 |
int arr[5] = {1, 2, 3, 4, 5}; |
This initializes an array of size 5, with the elements {1, 2, 3, 4, 5} in order.
This means that arr[0] = 1, arr[1] = 2, and so on.
We don’t need to initialize all the elements 0 to 4. We can even do only from indices 0 to 2.
The following code is also valid:
|
1 |
int arr[5] = {1, 2, 3}; |
But now, arr[4] and arr[5] will still remain garbage values, so you need to be careful!
If you’re using an initializer list with all elements, you don’t need to mention the size of the array.
|
1 2 3 4 5 |
// Valid. Size of the array is taken as the number of elements // in the initializer list (5) int arr[] = {1, 2, 3, 4, 5}; // Also valid. But here, size of a is 3 int a[] = {1, 2, 3}; |
If you want to initialize all the elements to 0, there is a shortcut for this (Only for 0). We can simply mention the index as 0.
|
1 2 3 4 5 6 7 8 9 10 11 |
#include <stdio.h> int main() { // You must mention the size of the array, if you want more than one // element initialized to 0 // Here, all 5 elements are set to 0! int arr[5] = {0}; for (int i=0; i<5; i++) { printf("%dn", arr[i]); } return 0; } |
Output
|
1 |
If you’re using multi-dimensional arrays, you can still initialize them all in one block, since arrays are stored in a row-wise manner.
|
1 2 3 4 5 6 7 8 |
#include <stdio.h> int main() { int arr[3][3] = {1,2,3,4,5,6,7,8,9}; for (int i=0; i<3; i++) for (int j=0; j<3; j++) printf("%dn", arr[i][j]); return 0; } |
Output
|
1 2 3 4 5 6 7 8 9 |
1 2 3 4 5 6 7 8 9 |
A similar method can also be used for other datatypes, like float, char, char*, etc.
|
1 2 3 4 5 6 7 8 |
#include <stdio.h> int main() { // Array of char* elements (C "strings") char* arr[9] = { "Hello", [1 ... 7] = "JournalDev", "Hi" }; for (int i=0; i<9; i++) printf("%sn", arr[i]); return 0; } |
Output
|
1 2 3 4 5 6 7 8 9 |
Hello JournalDev JournalDev JournalDev JournalDev JournalDev JournalDev JournalDev Hi |
Remember, this method with [1 … 7] = “Journaldev” might not work with all compilers. I work on GCC in Linux.
Method 2: Initialize an array in C using a for loop
We can also use the for loop to set the elements of an array.
|
1 2 3 4 5 6 7 8 9 10 |
#include <stdio.h> int main() { // Declare the array int arr[5]; for (int i=0; i<5; i++) arr[i] = i; for (int i=0; i<5; i++) printf("%dn", arr[i]); return 0; } |
Output
|
1 2 3 4 |
1 2 3 4 |
Method 3: Using Designated Initializers (For gcc compiler only)
If you’re using gcc as your C compiler, you can use designated initializers, to set a specific range of the array to the same value.
|
1 2 3 |
// Valid only for gcc based compilers // Use a designated initializer on the range int arr[9] = { [0 ... 8] = 10 }; |
Note that there is a space between the numbers and there are the three dots. Otherwise, the compiler may think that it is a decimal point and throw an error.
|
1 2 3 4 5 6 7 |
#include <stdio.h> int main() { int arr[9] = { [0 ... 8] = 10 }; for (int i=0; i<9; i++) printf("%dn", arr[i]); return 0; } |
Output (for gcc only)
|
1 2 3 4 5 6 7 8 9 |
10 10 10 10 10 10 10 10 10 |
We can also combine this with our old initializer list elements!
For example, I am setting only array index arr[0], arr[8] as 0, while the others are designated initialized to 10!
|
1 2 3 4 5 6 7 |
#include <stdio.h> int main() { int arr[9] = { 0, [1 ... 7] = 10, 0 }; for (int i=0; i<9; i++) printf("%dn", arr[i]); return 0; } |
Output
|
1 2 3 4 5 6 7 |
10 10 10 10 10 10 10 |
Conclusion
In this article, we learned how we could initialize a C array, using different methods.
For similar articles, do go through our tutorial section on C programming!